Assembly - Add 2 interger number
Using AT&T syntax. First, is integer to string. We will divide 10 and push remainderto stack. Finish when result by 0. Pop from stack, and add 48 to convert to ascii charater. Now, you can print number: .data a: .int 123 b: .int 10 c: .int 0 thuong: .int 0 du: .int 0 Enter: .int 10 s: .ascii "1" .text .globl _start _start: #nap so can in vao eax movl a,%eax movl $0,%ecx #tach so tach: movl $0,%edx #chia cho 10 divl b #push so du vao addl $48,%edx pushl %edx inc %ecx cmp $0,%eax jne tach in: popl %eax #luu ecx movl %ecx,c #in movl %eax,du movl $4,%eax movl $1,%ebx movl $du,%ecx movl $1,%edx int $0x80 #tra ecx movl c,%ecx loop in exit: movl $1,%eax movl $0,%ebx int $0x80 Soure: http://www.mediafire.com/?m8hzcrvum926878 And full source to print negativ